Angular acceleration and angular velocity

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The discussion revolves around calculating the angular acceleration and angular velocity of a 4 kg object rotating in a circle with a radius of 3 m over 6 seconds. Participants express confusion over the question's wording, noting that angular acceleration is typically perpendicular to radial motion and that the provided formula for angular acceleration is incorrect. They suggest that the question likely intends for the calculation of radial (centripetal) acceleration instead, as the angular acceleration cannot be determined with the given information. Assuming the object completes one full rotation in 6 seconds, the angular velocity is calculated to be approximately 1.04 rad/sec. Overall, the consensus is that the question lacks sufficient data to accurately determine angular acceleration.
John78
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Homework Statement



Calculate the angular acceleration and angular velocity of a 4 kg object rotating in a circle of 3 m radius in a time of 6 s.


Homework Equations



Angular acceleration = ω2*r

Angular velocity= angular displacement/time ?


The Attempt at a Solution



Really don't know how to start :C
 
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hmm. It might help if you went over some of the topics of circular motion. Also, the question is badly worded or incomplete? Angular acceleration is a term usually used for the acceleration which is perpendicular to the radial motion. So it is not omega squared times r. The radial acceleration is usually used for omega squared times r.

But with what the question gives you, it looks like the angular acceleration cannot be found, although the radial acceleration can. So I think you can assume you are meant to work out the radial acceleration.

Another problem with the question is that it doesn't explicitly say how far the object moves in that 6 seconds. But at a first guess, I'd say you are meant to assume it completes one full rotation in 6 seconds.

So, assuming the object completes one full rotation in 6 seconds, then what is the angular velocity? You've written the equation: "Angular velocity= angular displacement/time" so what is the 'angular displacement' for one full rotation?
 
My calculation looks like that

Angular velocity:

360/57.3=6.28 rad/s

6.28 rad/s / 6= 1.04 rad/sec


but what about angular acceleration?

Am I right i thinking?
 
The time period is given to you as 6 seconds.
You need ##\omega## (angular velocity).

##Period = \frac{2 \pi}{\omega}##

For, angular acceleration, I think the data is incomplete because angular acceleration ##\alpha=\frac{d\omega}{dt}##. So you need more values.
 
John78 said:
My calculation looks like that

Angular velocity:

360/57.3=6.28 rad/s

6.28 rad/s / 6= 1.04 rad/sec

Yep, this is right. (Although, it is 6.28 rad, and it only gets the units of rad/sec when you divide by time). The question asks about angular acceleration, but as warlock says, the angular acceleration cannot be found. So it is more likely that the question meant radial acceleration (aka centripetal acceleration). And you do have the correct equation for this.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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