Angular acceleration of a bar on a hinge

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SUMMARY

The discussion centers on calculating the angular displacement of a bar on a hinge, given an angular acceleration function of \(\alpha(t) = 10 + 6t\) rad/s² over the first 4 seconds. To find the angular displacement, one must integrate the angular acceleration function twice with respect to time. The first integration yields the angular velocity function, and the second integration provides the angular displacement, incorporating appropriate constants of integration based on boundary conditions.

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Homework Statement


A bar on a hinge starts from rest and rotates with [tex]\alpha[/tex]=(10+6t) rad/s2 t is in seconds. Determine the angle in radians the bar turns in the first 4 seconds.


Homework Equations


I'm a little stumped how to get this one started. I assume i need to get it from angular acceleration to angular displacement, but I'm not exactly sure how to do that. So do I have to integrate it with respect to time twice?


The Attempt at a Solution

 
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That's right. Remember to use constants of integration/ boundary conditions in general (although it should make no difference in this case).
 

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