Angular acceleration of a drill

notsam
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Homework Statement

A dentist’s drill starts from rest. After 3.07 s
of constant angular acceleration, it turns at a
rate of 24400 rev/min.
Find the drill’s angular acceleration.
Answer in units of rad/s2.



Homework Equations

F=mv^2/r, vi=vf+at, a=v^2/r



The Attempt at a Solution

The part that I don't understand is how 2440 rev/min is related to the other units. If I knew this I could probably solve it.
 
on Phys.org
how many radians will be covered one revolution ?

just put that and use 60s for 1min .. you'get speed in rad/s
 
And rads/sec can be used as a velocity?
 
rad/s is angular velocity... 2(pi) rad = 1 rev i believe
 
use eqn of on velocity not linear velocity to solve this question

w = wo + αt
 
Thanks! This isn't part of the homework but I am curious because my teacher said that it would be on the test, what if I wanted to find the angle that the drill rotates? Since I have 24400 rev/min = 2555 rad/sec over an interval of 3.07 s, I would multiply 2555 x 3.07 which would give me radians and then convert it to degrees?
 
all the Newton eqn's are valid for rotation in angular form

2555 x 3.07 will not work as you have acceleration

Try this:

θ = wot + 0.5αt2

Which come from

s = ut + 0.5at2
 
*just use:

s = θr
v = wr
a = αr


for all Newton eqn to convert them to rotation one ! :)
 
No way? So when it's at rest it simplifys to s=.5at^2? And s= arc legth in radians?
 
  • #10
notsam said:
No way? So when it's at rest "initially" it simplifys to s=.5at^2? And s= arc legth in radians?
length cannot be in radian ... rad is a pure number .. length is in meters
 
  • #11
Ok so the basic kinematic equation for distance can also be used for angles when using angular acceleration. That is SO helpful that just opened up a door in my mind I understand this matertial so much more now!
 
  • #12
Yes they can be
i already gave you 2

last one is : w2 = wo2 + 2αθ
 
  • #13
2555 rads/sec is the final velocity after 3.07 seconds of constant acceleration.
 

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