Angular acceleration of a planet

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In a star-planet system, an object farther from the center experiences different centripetal acceleration due to its orbital speed. Although gravitational force decreases with distance (F = GmM/r^2), the planet's slower speed at a larger radius results in lower centripetal acceleration. The discussion highlights that in circular motion, acceleration is related to changes in velocity, which includes direction. The original poster expresses confusion about whether planetary examples accurately reflect the principles discussed. The conversation suggests consulting additional resources for clarity on this topic.
itachipower
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So my teacher said that an object farther from the center experiences greater centripetal acceleration. How is that possible? let's say we have a sun + planet system. F = GmM/r^2 so when the planet's r is greater, wouldn't the force become lower compared to the planet being closer to the sun?
 
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When the planet's r is greater... the fource would become lower compared to the planet being FARTHER from the sun.

Also, call it star, not Sun. The Sun is our star
 
gabriel.dac said:
When the planet's r is greater... the fource would become lower compared to the planet being FARTHER from the sun.

Also, call it star, not Sun. The Sun is our star

What if it was a ball attached to a string? How would that be different from a binary planet-star system?
 
itachipower said:
What if it was a ball attached to a string? How would that be different from a binary planet-star system?

The planet would have smaller centripetal acceleration because it would be moving slower than if it was closer to the Sun. It needs less speed to stay in orbit
 
gabriel.dac said:
The planet would have smaller centripetal acceleration because it would be moving slower than if it was closer to the Sun. It needs less speed to stay in orbit

Speed isn't a proper term in physics. In the case of circular motion, it's velocity that represents both (1) the rate of motion and (2) the direction.

Acceleration, on the other hand, is the change in velocity over time. Which is constantly changing direction in circular motion, albeit uniformly.

PF indicates a larger orbit will have a larger centripetal acceleration. See thread link in my next post.
 
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itachipower said:
So my teacher said that an object farther from the center experiences greater centripetal acceleration. How is that possible? let's say we have a sun + planet system. F = GmM/r^2 so when the planet's r is greater, wouldn't the force become lower compared to the planet being closer to the sun?

Your teacher is correct. Physics Forum indicates so in a planetary example, but I'm wondering if planet's orbits are a proper example.

I'm having some doubts about the OP question - if planets are the example the textbook had in mind. If the period of the circular motion stays constant, the acceleration is obviously greater the further from the center. But gravitational orbits...

There's a homework help thread on this exact question here:
www.physicsforums.com/showthread.php?t=548403

Hope a PF expert will reply and help sort this out.
 
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I have recently been really interested in the derivation of Hamiltons Principle. On my research I found that with the term ##m \cdot \frac{d}{dt} (\frac{dr}{dt} \cdot \delta r) = 0## (1) one may derivate ##\delta \int (T - V) dt = 0## (2). The derivation itself I understood quiet good, but what I don't understand is where the equation (1) came from, because in my research it was just given and not derived from anywhere. Does anybody know where (1) comes from or why from it the...

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