Angular Acceleration of a Rotating Wheel: Solving a Common Question

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The discussion revolves around solving a physics problem involving a wheel with constant angular acceleration. Initially, the wheel has an angular velocity of 2 rad/s and turns 5 complete revolutions in 2 seconds. Participants clarify that the problem does not imply a change in angular acceleration but rather asks for its calculation based on given values. The formula for angular motion is discussed, equating angular displacement to the initial velocity and angular acceleration. The key takeaway is that the constant angular acceleration can be determined using the provided data and relevant equations.
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Can anyone help me in solving this question?

At t=0, a wheel is rotating about a fixed axis at a constant angular acceleration has an angular velocity of 2 rad/s. Two seconds later it has turned 5 complete revolutions what is the angular acceleration of this wheel??
 
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The question says that the angular acceleration is constant, so why would it have changed two seconds later? Are you sure you were not asked to solve for the angular velocity?
 
I typed the question just as it was written. I am having trouble finding the formula for the solution, maybe it is written wrong??
 
I would say that the first step is to write the angular velocity of the wheel as a function of time. Have you tried to do this at all?
 
cepheid said:
The question says that the angular acceleration is constant, so why would it have changed two seconds later? Are you sure you were not asked to solve for the angular velocity?

The problem didn't say the angular acceleration had changed. It gave the initial angular velocity and the total angle moved in 2 seconds and asked you to calculate the constant angular acceleration.

mickeychief: this is just like straight line acceleration except that you use angles instead of length:
If the accelaration is a, then the velocity after t is at+ v0,where v0 is the initial velocity, and the "distance" moved is (1/2)at2+ v0t. Since you are told that v0= 2 rad/sec and that, with t= 0, the angle ("distance") moved was
"5 complete revolutions"= 5(2pi)= 10pi radians, you have
(1/2)a(4)+ 2(2)= 10pi. Solve for a.
 
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