# Angular and linear velocity of a rigid body given a force.

1. Jan 12, 2014

### calvinwylie

Hello,

I'm trying to prove a simulation of mine is working correctly. the simulation has a cube of sides 1, mass 1 and c.o.m. position at (0,0,0.5) ie sitting on the xy plane. i have a force along the x axis of 10. Is there anyway given those two, that i can work out the resulting ω and v of the body? the cube is unconstrained.

this is my first post, so if I've done something wrong i apologise.

Thanks

2. Jan 13, 2014

### calvinwylie

ok so i think i've found this:

ω = I-1Lp

where I-1 is the inverse of the inertia tensor. Lp is the angular momentum of the point the force is exerted on.

Lp = s x Mv.

where s is the position vector of the point relative to the center of mass. M is mass of the object and v is the velocity of the com.

Can someone at least tell me if this is correct?

3. Jan 13, 2014

### facenian

How is (0,0,0.5) on the xy plane? One ussually takes the order (x,y,z)

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