Angular Distance & Arc Distance: Homework Solution

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SUMMARY

The discussion focuses on calculating angular distance and arc distance for a boat traveling in a circular path. The boat maintains a uniform speed of 12.5 m/s with a diameter of 115 m, resulting in a radius of 57.5 m. Over a duration of 4 minutes, the boat travels an arc distance of 3,000 m, while the angular distance can be derived using the relationship between linear and angular velocity. The key takeaway is the importance of using angular velocity (ω) for circular motion calculations.

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  • Understanding of circular motion concepts
  • Knowledge of angular velocity (ω) and its relationship to linear velocity
  • Familiarity with basic kinematic equations
  • Ability to convert units of time and distance
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  • Learn how to calculate angular velocity from linear velocity
  • Explore the relationship between arc length and radius in circular motion
  • Study the formulas for angular distance in rotational dynamics
  • Practice problems involving circular motion and uniform speed
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Students studying physics, particularly those focusing on mechanics and circular motion, as well as educators looking for practical examples of angular and arc distance calculations.

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Homework Statement


The driver of a boat sets the throttle and ties the wheel, making the boat travel at a uniform speed of 12.5m/s in a circle with a diameter of 115m. Through what angular distance does the boat move in 4.00 minutes? What arc distance (in meters) does it travel in this time?


Homework Equations





The Attempt at a Solution



The diameter is 115m, radius is 57.5m, time is 4 min.

But noww is the average velocity 12.5m/s or is 12.5m/s final speed? I know that it is going at constant speed and it does have acceleration. So we take 12.5m/s x 240sec = 3,000m But for the arc distance you take the radius of 57.5 x 2pi(57.5) = 20,763m?
 
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You are trying to use the instantaneous velocity as if it were an angular quantity.

When working with speeds of things rotating or traveling in circles, what you want is the angular velocity \omega.
So find out how to find what the angular velocity is given the instantaneous velocity.
 
Ohh so their somewhat the same just use it differently. Much thanks! :]
 

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