Angular Momentum of a Moving Particle

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SUMMARY

The discussion centers on the angular momentum of a point particle moving in a straight line at constant speed, with the closest distance to the origin being distance l. It is established that the angular momentum L, defined by the equation L = r x p, remains constant due to the absence of external torques. However, the position vector r changes over time, leading to a nuanced understanding that while the magnitude of angular momentum remains constant, its direction does change as the particle moves along its path.

PREREQUISITES
  • Understanding of angular momentum concepts
  • Familiarity with vector cross product operations
  • Knowledge of linear momentum principles
  • Basic grasp of torque and its effects on motion
NEXT STEPS
  • Study the implications of the equation L = r x p in various motion scenarios
  • Explore the effects of external torques on angular momentum
  • Investigate the relationship between linear momentum and angular momentum
  • Learn about conservation laws in physics, specifically angular momentum conservation
USEFUL FOR

Students of physics, educators teaching mechanics, and anyone interested in the principles of angular momentum and motion dynamics.

Mark Zhu
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Homework Statement


A point particle travels in a straight line at constant
speed, and the closest distance it comes to the origin of coordinates
is a distance l. With respect to this origin, does the particle
have nonzero angular momentum? As the particle moves along its
straight-line path, does its angular momentum with respect to the
origin change?

Homework Equations


L = r x p

The Attempt at a Solution


Since there are no external torques applied to this particle system, I assume the angular momentum doesn't change. However, since the position vector of the particle changes over time and the linear momentum vector remains constant, wouldn't the angular momentum vector also change looking at the L = r x p
equation?
 
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Mark Zhu said:

Homework Statement


A point particle travels in a straight line at constant
speed, and the closest distance it comes to the origin of coordinates
is a distance l. With respect to this origin, does the particle
have nonzero angular momentum? As the particle moves along its
straight-line path, does its angular momentum with respect to the
origin change?

Homework Equations


L = r x p

The Attempt at a Solution


Since there are no external torques applied to this particle system, I assume the angular momentum doesn't change. However, since the position vector of the particle changes over time and the linear momentum vector remains constant, wouldn't the angular momentum vector also change looking at the L = r x p
equation?
I see this is marked solved. Please confirm with a post to the thread.
 
Yes, it is solved. Thanks.
 

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