1. The problem statement, all variables and given/known data A physical pendulum consists of a small 1.5kg mass at the bottom end of a uniform 1.00m long 1.5kg stick swinging about its upper end. The moment of inertia of the pendulum about its upper end is 2.00kg*m^2. What is the angular frequency 2. Relevant equations sqrt(mgd/I)=w I = I(cm)+md^2 = I = (1/3)(1.5)(1^2)+ (1.5)(d^2) = 2 3. The attempt at a solution m = 1.5+1.5 g = 9.81 d = 1 I = 2 w = sqrt([3*9.81*1]/2) = 3.83 rad/s According to my solutions manual this is wrong and the correct answer is 3.32 rad/s and somehow d = .75. I don't know how they calculated that, can anyone help?