Angular Momentum and Angular kinetic energy about the center of the sun.

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SUMMARY

The discussion focuses on calculating the Earth's angular momentum about the center of the sun, given its distance of approximately 1.5x10^8 km and mass of 5.97x10^24 kg. The key distinction made is between angular velocity and tangential velocity, where angular velocity is represented as 2π/time and tangential velocity as 2πr/time. The relationship between these velocities is established through the equation v = ωr, which is crucial for understanding kinetic energy in rotating systems.

PREREQUISITES
  • Understanding of angular momentum and its calculation.
  • Familiarity with angular and tangential velocity concepts.
  • Knowledge of kinetic energy equations, including rotational kinetic energy.
  • Basic grasp of circular motion principles.
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  • Research the formula for angular momentum in different systems.
  • Learn about the conservation of angular momentum in astrophysical contexts.
  • Study the relationship between angular velocity and tangential velocity in depth.
  • Explore examples of rotational kinetic energy in various physical systems.
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Students studying physics, particularly those focusing on mechanics and rotational dynamics, as well as educators teaching concepts related to angular momentum and kinetic energy.

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Homework Statement


The Earth is approximately 1.5x10^8 km from the sun. what is the Earth's angular momentum about the center of the sun. Note the mass of the Earth is 5.97x10^24.


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The Attempt at a Solution


I got the answer, but my question is, when finding the velocity: which is 2pir/time the Earth takes to revolve, do we use 2pi/time or 2pir/time. i have this question because my teacher in some examples uses r and in some doesnt. Can someone help me with when and why we use the radius?
 
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It's to differentiate between angular and tangential velocity.

Angular velocity: dθ/dt
Tangential velocity: ds/dt = r*dθ/dt, since s = θ*r.

So, when it says 2π/time, it's angular velocity, and when it says 2πr/time it's tangential velocity. For example, say you have a ball rolling on very slippery ice. It's kinetic energy isn't just ½mv2 but also ½Iω2, since it's also rotating. These velocities can be converted into one another due to the relation v = ωr.
 
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