Angular momentum conservation: determine velocity of impactor

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SUMMARY

The discussion focuses on a physics problem involving the conservation of angular momentum during a collision between a particle and a uniform rod. The rod, with length L and mass M, is struck by a particle of mass m at a distance of 0.8L from the pivot. The particle's velocity v is to be determined, given that the rod reaches a maximum angle of 90 degrees post-collision. Key equations related to moment of inertia and angular motion are referenced, with the user indicating a need for additional equations to finalize the solution.

PREREQUISITES
  • Understanding of angular momentum conservation principles
  • Familiarity with moment of inertia calculations for rigid bodies
  • Knowledge of rotational kinematics and dynamics
  • Ability to apply the arclength equation S = rθ in rotational motion
NEXT STEPS
  • Study the derivation of moment of inertia for a uniform rod
  • Learn about angular momentum conservation in inelastic collisions
  • Explore the relationship between linear velocity and angular velocity
  • Investigate the use of energy conservation principles in rotational motion
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators seeking to enhance their understanding of angular momentum and collision problems.

Vitani11
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Thread title changed to reflect problem description

Homework Statement


A uniform rod of length L and mass M hangs at rest from a frictionless pivot. The rod is hit a distance 0.8L below the pivot by a particle of mass m moving perpendicularly to the rod at speed v; the particle sticks to the rod. Following the collision, the maximum angle between the rod and the vertical is 90 deg. What is v?

Homework Equations


See attached

The Attempt at a Solution


See attached
 
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This is where I'm at. I need another equation for t in terms of moment of inertia, mass, or radius. At least I am about 80% sure that is all I need left to solve this.
 

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In case you're wondering where ωf came from: It is the arclength equation S=rθ divided by time, where theta was given as π/2 (90 deg) and r is L.
 

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