Angular momentum conservation: determine velocity of impactor

In summary, a uniform rod of length L and mass M is hanging at rest from a frictionless pivot. A particle of mass m moving perpendicularly to the rod at speed v hits the rod at a distance 0.8L below the pivot and sticks to it. After the collision, the maximum angle between the rod and the vertical is 90 deg. The equation for solving this problem involves finding an equation for t in terms of moment of inertia, mass, or radius. ωf is the arclength equation S=rθ divided by time, where theta is π/2 (90 deg) and r is L.
  • #1
Vitani11
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3
Thread title changed to reflect problem description

Homework Statement


A uniform rod of length L and mass M hangs at rest from a frictionless pivot. The rod is hit a distance 0.8L below the pivot by a particle of mass m moving perpendicularly to the rod at speed v; the particle sticks to the rod. Following the collision, the maximum angle between the rod and the vertical is 90 deg. What is v?

Homework Equations


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The Attempt at a Solution


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  • #2
This is where I'm at. I need another equation for t in terms of moment of inertia, mass, or radius. At least I am about 80% sure that is all I need left to solve this.
 

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  • #3
In case you're wondering where ωf came from: It is the arclength equation S=rθ divided by time, where theta was given as π/2 (90 deg) and r is L.
 

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