(adsbygoogle = window.adsbygoogle || []).push({}); A hydroxyl radical (O-H*) in the gas phase is found to be in a rotational state with a given wavefunction (Long wavefunction, not needed for my questions).

Calculate the expected value of L_{z}(angular momentum in z) for the radical.

Is this the right equation?

L_{z}=m_{l}ħ ????

In which orbital is the radical? How do I figure this out?

The orbital of the radical (not sure how to find this) would give me the rotational quantum number (l), thus giving me the spacial orientation quantum number (m_{l}), with which I could solve for L_{z}=m_{l}ħ[/QUOTE] But then why does the problem give a wavefunction?

Information:

ħ = h/2[tex]\pi[/tex]

[tex]h\ =\ 6.62606876(52)\ \times\ 10^{-34}\ J\ s[/tex]

m_{l}= -l, -l+1, -l+2, ... l-2, l-1, l

H orbital 1s^{1}

O orbital 1s^{2}2s^{2}2p^{4}.

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# Angular momentum (L) in z-axis of hydroxyl radical

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