Angular Momentum of 2kg Particle Moving at 4.5m/s

[Rasine]

a 2-kg particle moves at a constant speed of 4.5 m/s along a stright line. what is the magnitude of its angular momentum about a point 6 m from the line?

ok...so i really don't know what they mean by 'the particle is travling in a stright line about a point 6m away from the line'

doesn't angular momentum imply that the particle is travling in a circular path?

so i attemped this and L=Iw

w=rv and if the particle is travling about a point 6 m away, then the r should be 6

so L=Irv


but now for I...i don't know what to use because i am not sure how the particle is moving

but if it is moving in a cirlce as i think it should I=(2/3)mr^2

please help me to picture this problem

 

[Dick]

You'll want to use the definition of angular momentum L=m*(rxv), where x is the cross product. Review this formulation for noncircular motion.