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Angular Momentum Operator in terms of ladder operators

  1. Mar 8, 2010 #1
    Last edited by a moderator: Apr 24, 2017
  2. jcsd
  3. Mar 8, 2010 #2

    Ben Niehoff

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    You missed the

    [tex]e^{\pm i \phi}[/tex]

    in the definition of [itex]L_{\pm}[/itex]
  4. Mar 8, 2010 #3
    dont they multiply to give 1?

    [tex]e^{ i \phi}e^{- i \phi} = 1[/tex]


    you were right, i got it in the end taking into account the exponential factors...was a ***** of an algebra grindfest though
    Last edited: Mar 8, 2010
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