Angular Momentum Operator in terms of ladder operators

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  • #2
Ben Niehoff
Science Advisor
Gold Member
1,879
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You missed the

[tex]e^{\pm i \phi}[/tex]

in the definition of [itex]L_{\pm}[/itex]
 
  • #3
You missed the

[tex]e^{\pm i \phi}[/tex]

in the definition of [itex]L_{\pm}[/itex]

dont they multiply to give 1?

[tex]e^{ i \phi}e^{- i \phi} = 1[/tex]

Edit:

you were right, i got it in the end taking into account the exponential factors...was a ***** of an algebra grindfest though
 
Last edited:

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