# Angular Momentum Operator in terms of ladder operators

1. Mar 8, 2010

### Plutoniummatt

Last edited by a moderator: Apr 24, 2017
2. Mar 8, 2010

### Ben Niehoff

You missed the

$$e^{\pm i \phi}$$

in the definition of $L_{\pm}$

3. Mar 8, 2010

### Plutoniummatt

dont they multiply to give 1?

$$e^{ i \phi}e^{- i \phi} = 1$$

Edit:

you were right, i got it in the end taking into account the exponential factors...was a ***** of an algebra grindfest though

Last edited: Mar 8, 2010