Minimum radius for plane to turn upward at 770 km/h with 9g acceleration limit

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SS2006
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The human body can safely stand an acceleration 9 times that due to gravity. With what minimum radius of curvature may a pilot sfely turn the plane upward at the end of a dive if the plane's speed is 770km/h.


i did a quesotin before this, which had a roller coaster
i did mgh at a = 1/2 mv square at a + mgh b. my v square was derived
froma free body diagram i drew, and i set mvsquare/r = fnet
and rearranged until i had the equation equal to V.
and then solved for H (from mgh at a) and i got the answer.
For this i don't know wat to do, can i use the same formula, but i don't have both heights, just the first one
i just wanted a startup
 
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The problem has to do with centripetal acceleration.

Can you see how to set up eqns for centripetal acceln/force from the info given ?
 
energy isn't necessary for this question. It's all centripetal motion.
 
reallyy! so this is different from the roller coaster q
im surprised now
what formulas may help
 
What is the formula for the centripetal force on a body traveling in a circle,of radius R, with an angular velocity of ω ?
 
v = w square tiems r?

or
mv square over r
 
Last edited:
SS2006 said:
v = mv square over r

Ok, this becomes,

Fc = mv²/r

and you want to find r.

What is the maximum value that Fc can be such that the pilot only experiences 9g ?

Then solve for r.
 
ans...518.69 meters
how disgracful of u guys. can't even solve such easy question.
haha...got outbeaten by a 14 year old nutcase
 
vijay123 said:
ans...518.69 meters
how disgracful of u guys. can't even solve such easy question.
haha...got outbeaten by a 14 year old nutcase
It is much more productive, if one guides a poster through the question rather than providing answers or solutions. What has SS2006 gained from your post?
 
One would hope only confirmation, because if he's still waiting on an answer then his assignment might be a bit late. ;)
 
Hawknc said:
One would hope only confirmation, because if he's still waiting on an answer then his assignment might be a bit late. ;)
Didn't spot the date:wink:
 
lol...sry guys..i jus did dat for fun...
ok here it goes...
mv(squared)/radius=m9g
if you sub. in the values of the porblem by making r the subject of the formula, i got the ans.
radius=v(sqaured)/9g
were v is velcity, m is mass and g is 9.8ms(sqaured).
remeber to convert the km/h into m/sec.
sry for any hurt feelings
that wus jus for fun,
regards
vijay
 
lol, i glanced through the pages and found this, the prob. wus easy yet know one gave a definite ans to the solution. that's were i budged in...sry..guys.