1. The problem statement, all variables and given/known data An 82 kg pilot flying a stunt airplane pulls out of a dive at a constant speed of 540 km/h. a) What is the minimum radius of the plane's circular path if the pilot's acceleration at the lowest point is not to exceed 7.0g. 2. Relevant equations Fg = mg Fnet = mv^2/r Fnet = ma 3. The attempt at a solution At the lowest point I said that there were only 2 forces acting on the plane: Fg and I said Fn for the upward lift on the plane. m=82 kg v=540 km/h=150 m/s a=7.0g Fnet = mv^2/r=ma Fnet = Fn - Fg = ma Fnet = (82 kg)(7 x 9.8 N/kg) - (82 kg)(9.8 N/kg) = 4821.6 N = mv^2/r 4821.6 N = [(82 kg)(150 m/s)^2]/r r=[(82 kg)(150 m/s)^2]/4821.6 N = 382.65 m = 3.8 x 10^2 m The answer is actually 3.3 x 10^2 m... The book is sometimes wrong though. What did I do wrong? Thanks.