Consider two particles A and B. The angular position of particle A, with constant angular acceleration, depends on time according to theta(t)=theta_0+omega_0t+alpha t^2. At time t=t_1, particle B, which also undergoes constant angular accelaration, has twice the angular acceleration, half the angular velocity, and the same angular position that particle A had at time t=0.(adsbygoogle = window.adsbygoogle || []).push({});

How long after the time t_1 does the angular velocity of B have to be to equal A's?

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ok, here we go:

i know that i have to write expressions for the angular velocity of A and B as functions of time, and solve for t-t1???

For A, omega(t) = omega_0 + alpha(t) and

for B, omega(t) = 0.5 omega_0 + 2alpha(t-t_1)

so when i equate them and solve for t-t_1, i get something that is not the right answer!

please help :(

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# Homework Help: Angular motion with constant acceleration

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