Angular relationship question.

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SUMMARY

The discussion centers on calculating the horizontal displacement of a model rocket launched at 50 m/s at an angle of 35 degrees, specifically when its velocity vector is at 25 degrees. The user applies kinematic equations and the relationship between sine, cosine, and tangent to derive the equations for vertical and horizontal velocities. However, the user expresses confusion regarding the application of gravity's effect on the rocket's velocity and the resulting time calculation, which they find suspicious. The conclusion indicates a need for clarity on how gravitational deceleration impacts the horizontal displacement calculation.

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Homework Statement


A model rocket is launched at 50m/s, 35 degrees above horizontal. What is the horizontal displacement when its velocity vector is at 25 degrees.


Homework Equations


Kinematic equations, the relationship between sin cos and tan.


The Attempt at a Solution


tan(25)= .4663. I interpret this as the y (sin) velocity being .4663 the x velocity. Vy = .4663Vx

Vy = 50sin(25)-9.8t
.4663Vx = 50sin(25)-9.8t
Vx = (50sin25-9.8t)/.4663
Vx also equals 50*cos25 therefore...
50cos25 = (50sin25-9.8t)/.4663
(.4663*50cos25-50sin25)/-9.8 = t
t = 3.54E^-5.

Something about this answer seems very very wrong, especially when plugged back into the x displacement equation.
 
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Vx also equals 50*cos25 therefore...

Why 50? The rocket decelerated due to gravity.
 

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