Find the speed of the object after 4 seconds

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SUMMARY

The discussion centers on calculating the speed of an object thrown horizontally after 4 seconds, where the speed vector forms a pi/4 radians angle with the horizontal after 3 seconds. The key equations used include v=gt for vertical velocity, resulting in a vertical speed (vy) of 40 m/s at t=4 seconds. The horizontal speed (vx) equals the vertical speed at the angle of pi/4 radians, leading to a resultant speed of 50 m/s calculated using the Pythagorean theorem. The only correction noted was regarding the units of measurement.

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annalian
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Homework Statement


An object is thrown horizontally and after 3 seconds the speed vector forms the angle pi/4 radians with the horizontal direction. FInd the speed after 4 seconds.

Homework Equations


v=gt

The Attempt at a Solution


As it forms the angle pi/4 radians, vx=vy, so
v0=gt=3*10=30
vy when t=4 is 40m
v=sqrt(vx^2+vy^2)=50m Am I right
 
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annalian said:

Homework Statement


An object is thrown horizontally and after 3 seconds the speed vector forms the angle pi/4 radians with the horizontal direction. FInd the speed after 4 seconds.

Homework Equations


v=gt

The Attempt at a Solution


As it forms the angle pi/4 radians, vx=vy, so
v0=gt=3*10=30
vy when t=4 is 40m
v=sqrt(vx^2+vy^2)=50m Am I right
Right.
 
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cnh1995 said:
Right.
Except for the units.
 
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