A merry go round can be described as a horizontal platform in the shape of a disc which rotates on a frictionless bearing about a vertical axis through its centre. The platform has a mass of 150 kg, a radius of 2.0 m and a rotational inertia of 300 kg.m2.A 60 kg student walks slowly from the rim of the platform toward the centre. If the angular speed of the system is 1.5 rad.s-1 when the student starts at the rim, what is the angular speed when he is 0.5 m from the centre?(adsbygoogle = window.adsbygoogle || []).push({});

I know that w=2(pi)/T=2(pi)r and the kinetic energy= (mr^2w^2)/2, but I am not sure how these two are to be related, if these are the correct equation to begin with.

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# Homework Help: Angular speed of student on merry-go-round

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