Angular Velocity and Acceleration

AI Thread Summary
A car traveling at 27.8 m/s experiences a negative acceleration of 2.6 m/s² when brakes are applied, prompting a discussion on calculating the number of tire revolutions before coming to a stop. The initial angular velocity is derived from the linear velocity using the formula ω = v / r, resulting in an angular velocity of 27.8 rad/s. However, confusion arises regarding the constancy of angular velocity during deceleration, leading to the need for a more accurate approach to find the angular displacement. The correct method involves using the equation Θ = ω t + 0.5 α t² to account for changing angular velocity. Ultimately, the problem emphasizes the importance of understanding angular motion equations in relation to linear motion.
df102015
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Homework Statement


A car is traveling at 27.8 m/s, it undergoes a negative acceleration of 2.6 m/s/s when the brakes are applied. How many revolutions will the tires go through before the car comes to a stop if the wheels each have a radius of 1.0 m?

Homework Equations


α = at / r -> angular acceleration = tangential acceleration / radius
α = ω / t -> angular acceleration = angular velocity / time
α = Θ / t^2 -> angular acceleration = angle / time^2
ω = Θ / t -> angular velocity = angle / time
ω = v / r -> angular velocity = velocity / radius

The Attempt at a Solution


ω = v / r
ω = 27.8 / 1
ω = 27.8

α = a / r
α = (- 2.6) / 1
α = -2.6

α = ω / t
-2.6 = 27.8 / t
27.8 / 2.6 = t
10.7sec = t

ω = Θ / t
27.8 = Θ / 10.7
Θ = 297.46°

297.46 / 360 = 0.83 times

This was incorrect.
 
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df102015 said:
ω = Θ / t
27.8 = Θ / 10.7
Θ = 297.46°
Careful. ω is not a constant.
 
df102015 said:
ω = Θ / t
What, exactly, does dividing an angular displacement by an elapsed time give you? Yes, it's an angular velocity, but what angular velocity?
 
Doc Al said:
Careful. ω is not a constant.

i'm not sure what you mean by that... are you saying that ω is not 27.8 ?
How would i solve for ω the correct way?
 
haruspex said:
What, exactly, does dividing an angular displacement by an elapsed time give you? Yes, it's an angular velocity, but what angular velocity?
the angular velocity of the wheel?
 
df102015 said:
i'm not sure what you mean by that... are you saying that ω is not 27.8 ?
How would i solve for ω the correct way?
I assume you are familiar withthe SUVAT equations for linear motion at constant acceleration. It's just the same for angular motion.
 
df102015 said:
the angular velocity of the wheel?
As Doc Al posted, that is not constant here. So the angular velocity when?
 
haruspex said:
I assume you are familiar withthe SUVAT equations for linear motion at constant acceleration. It's just the same for angular motion.
Yes and so would i use Θ = ω t + 0.5 α t^2 ?
and ω would be the angular velocity of the wheel before deceleration?
 
df102015 said:
Yes and so would i use Θ = ω t + 0.5 α t^2 ?
and ω would be the angular velocity of the wheel before deceleration?
Yes.
 
  • #10
df102015 said:
Yes and so would i use Θ = ω t + 0.5 α t^2 ?
and ω would be the angular velocity of the wheel before deceleration?
You're given the linear velocity of the car before deceleration and the radius of the wheels. Don't you think that there is some formula which can relate these two pieces of information?
 
  • #11
SteamKing said:
You're given the linear velocity of the car before deceleration and the radius of the wheels. Don't you think that there is some formula which can relate these two pieces of information?
df102015 said:
ω = v / r
ω = 27.8 / 1
ω = 27
 
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