Angular velocity and regular velocity

Click For Summary
SUMMARY

The discussion centers on a physics problem involving a pole of mass M and length L on a frictionless table, which is struck by another particle of the same mass M with velocity V. The participant seeks to determine both the angular velocity and the linear velocity of the combined system after the collision. It is confirmed that conservation of linear momentum can be applied, leading to the equation mv = 2mv', where v' represents the regular velocity of the new body formed after the collision.

PREREQUISITES
  • Understanding of conservation of linear momentum
  • Familiarity with Newton's second law
  • Basic knowledge of angular velocity concepts
  • Comprehension of center of mass principles
NEXT STEPS
  • Study the principles of conservation of momentum in two-dimensional collisions
  • Learn about angular momentum and its conservation
  • Explore the calculation of center of mass in composite systems
  • Review examples of inelastic collisions in physics
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators seeking to clarify concepts related to momentum and collisions.

asi123
Messages
254
Reaction score
0

Homework Statement



I have this pole with mass M and length L which is on a flat table with no friction. Another particle, which has the same mass M hits him on its edge with velocity V, which is vertical to the pole.
then, the particle sticks to the pole and they move together.
I need to find both the Angular velocity and the regular velocity of the new body.
My question is about the regular velocity, can I use the conservation of linear momentum law and say that mv = 2mv', and to find the regular velocity?
10x.

Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
asi123 said:
My question is about the regular velocity, can I use the conservation of linear momentum law and say that mv = 2mv', and to find the regular velocity?

Hi asi123! :smile:

Yes, you're right!

You can always use conservation of linear momentum in a direction if there are no external forces in that direction, because that's simply good ol' Newton's second law with a net force of zero. :wink:

Since there is no friction in this case, and the only external force is gravity, which is vertical, conservation of horizontal momentum will apply.

(don't forget that the centre of mass will be in a different place, of course)
 
10x.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
841
  • · Replies 17 ·
Replies
17
Views
1K
Replies
335
Views
17K
  • · Replies 12 ·
Replies
12
Views
2K
Replies
67
Views
5K
  • · Replies 30 ·
2
Replies
30
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
23
Views
2K
Replies
10
Views
3K
Replies
9
Views
3K