Angular Velocity/Motion Question

  • Thread starter Thread starter Victorzaroni
  • Start date Start date
  • Tags Tags
    Angular
Click For Summary

Homework Help Overview

The problem involves a bead sliding along a frictionless ring that rotates about a vertical axis. The objective is to determine the angle θ that the bead makes with the vertical given the ring's radius and angular velocity.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the use of free body diagrams to analyze forces acting on the bead, including gravitational force and normal reaction. There are attempts to relate the motion of the bead to angular velocity and radius through trigonometric relationships.

Discussion Status

The discussion has seen participants exploring different approaches to relate the forces and motion of the bead. Some have suggested using trigonometric functions to express relationships between the radius and angle, while others have raised questions about the correct interpretation of the radius in the context of the bead's motion.

Contextual Notes

Participants note the challenge of determining the correct radius for the bead's circular motion and the implications of using different radii in their calculations. There is also mention of constraints related to the domain of the inverse sine function in their attempts to solve for the angle.

Victorzaroni
Messages
46
Reaction score
0

Homework Statement



A bead of mass m is free to slide along a frictionless ring of radius R=.5 meters that rotates about the vertical axis with angular velocity ω=6 rad/sec as shown below. What angle θ with the vertical will the bead make?

The answer choices are:
(A) 90
(B) 61
(C) 56
(D) 34
(E) 29

This is from the Physics C Mechanics: Sample Exam III.

Homework Equations



I have no idea.

The Attempt at a Solution



I don't know where to start.
 

Attachments

  • photo.JPG
    photo.JPG
    8.2 KB · Views: 681
Physics news on Phys.org
Try to make Free body diagram , with all the forces
 
Okay, I did. I have an Fc pointing in, and an mg pointing down, but I'm still not seeing it.
 
see there will mg (weight )going downward and a normal reaction ,
then you take components of Normal reaction and solve :D
 
Here is the figure
 

Attachments

  • photo.JPG
    photo.JPG
    11.3 KB · Views: 855
ohh. okay. so we can use wr=v, and when Fn is mg, that way when we set up, the masses cancel, and we can solve for v. Thanks!
 
but remember in v=rw r is the radius of the motion of particle not the ring :O
 
oh. that's the d in your diagram. So the two radii are different. So how do I get this d?
 
simple trigo rsin(theta)= d
 
  • #10
but we don't have ø?
 
  • #11
I tried working it out multiple times, but no matter how I do it, with your d or without it, the fraction at the end never falls in the domain for the sin-1. Can you write out what you would do? Thanks for all your help so far, in my other posts too.
 
  • #12
Oh wait a minute, I think I got it. Perhaps d=rcosø? If so, then at the end, tan-1((w2r)/g)=ø=61, choice B.
 
  • #13
Yea , good going :)
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
5K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 2 ·
Replies
2
Views
6K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 22 ·
Replies
22
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 39 ·
2
Replies
39
Views
16K