Angular velocity of bicycle wheel

Click For Summary
The discussion revolves around calculating the angular velocity of a bicycle wheel given a linear velocity of 13.0 m/s and a wheel diameter of 0.660 m. The correct formula used is ω = v/r, leading to an initial calculation of 39.4 s-1. However, the confusion arises because the answer should be expressed in radians per second, which requires dividing by 2π, resulting in 6.27 radians per second, aligning with the option "e - none of the above." The thread highlights a common mistake regarding units in angular velocity calculations. Understanding the distinction between revolutions per second and radians per second is crucial for accurate results.
Nelson2436
Messages
5
Reaction score
0

Homework Statement


A bicycle rider is moving with a velocity of 13.0 m/s. What is the angular velocity of his wheels if they have a diameter of 0.660m? Assume the wheels are rolling without slipping.

a) 39.4 m/s
b) 19.7 m/s
c) 39.4 s-1
d) 4.29 s-1
e) none of the above

Homework Equations


v = ω r

The Attempt at a Solution


ω = v/r
ω = (13m/s) / (0.330m) = 39.4 s-1
This problem was given on a test, I put "c" and got it wrong. It seems very straightforward and I'm not sure where I went wrong. Is there a mistake in my work? I am thinking it was most likely a mistake with the grading machine but I just wanted someone to confirm before I talked to the teacher. Thanks.
 
Physics news on Phys.org
Your answer looks correct to me.
 
  • Like
Likes Nelson2436
Yes, your answer is definitely correct. Note that you almost don't need the question. Just looking at the choice of answers, and assuming each wrong answer corresponds to a single likely error, (c) stands out as the common theme.
 
  • Like
Likes Nelson2436
It's a units issue. The 39.4 technically has units of 'revolutions per second'. Divide by 2pi to get your answer in 'radians per second', which can be written as 1/second. This would make the correct result 6.27 radians per second, which matches up to 'e - none of the above'.
 
kboyer HCC said:
The 39.4 technically has units of 'revolutions per second'.
No, dividing tangential velocity by radius gives radians per second.
Anyway, this thread is three years old.
 
My mistake. I did a google search related to angular velocity of bikes and when this came up, I didn't look at the date stamp. The similar problems I was working on for my class included revolutions per second in their calculation and I jumped the gun.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 17 ·
Replies
17
Views
879
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 10 ·
Replies
10
Views
1K
Replies
7
Views
2K
Replies
67
Views
4K
Replies
3
Views
2K
  • · Replies 10 ·
Replies
10
Views
1K
Replies
9
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 12 ·
Replies
12
Views
1K