Another capacitor Laplace transform problem

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SUMMARY

This discussion focuses on solving a capacitor discharge problem using the Laplace transform. The user attempts to derive voltage expressions for two capacitors discharging through a resistor, leading to a coupled system of differential equations. The equations presented are \(\frac{Vc_1 - Vc_2}{R} = C_2\frac{dV_{C2}}{dt}\) and \(\frac{Vc_2 - Vc_1}{R} = C_1\frac{dV_{C1}}{dt}\). The key takeaway is the importance of correctly applying initial conditions to avoid trivial solutions in the system of equations.

PREREQUISITES
  • Understanding of Laplace transforms, specifically the formula L(\(\frac{d}{dt}y)(s)=sY(s)-y(0)\)
  • Knowledge of coupled differential equations in electrical circuits
  • Familiarity with capacitor discharge behavior and circuit analysis
  • Basic skills in algebraic manipulation of equations
NEXT STEPS
  • Research techniques for solving coupled differential equations in electrical circuits
  • Study the application of initial conditions in Laplace transforms
  • Explore the effects of capacitance ratios on circuit behavior
  • Learn about the implications of trivial solutions in differential equations
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Electrical engineers, physics students, and anyone involved in circuit analysis or studying capacitor behavior in electrical systems.

bitrex
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I'm trying to use the Laplace transform to work out another capacitor problem, the voltage as a function of time on a capacitor that's discharging into another capacitor through a resistor. It's the classic two capacitor problem, but I'd like to actually find an expression for the voltage as a function of time across the capacitor that's discharging and the capacitor that's charging. I've tried setting up a coupled differential equation, like this:

\frac{Vc_1 - Vc_2}{R} = C_2\frac{dV_{C2}}{dt}
\frac{Vc_2 - Vc_1}{R} = C_1\frac{dV_{C1}}{dt}

but of course when I take the Laplace transform and try to solve it algebraically I get a system of equations the equivalent of something like A = 5B and B = 4A, which is useless. Any tips on a better way of setting this up would be appreciated.
 
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I don't know about the laplace transform, but the current in the circuit is the same. so the right side of both equations is equal. integrate both sides and plug in any initial conditions? the problem maybe has to do with the ratio of capacitances.
 
The only way you could get an homogenous system of equations is by letting the initial conditions (voltage of the capacitors) be zero, then it's not a surprise you will get a trivial solutions.

Use

L(\frac{d}{dt}y)(s)=sY(s)-y(0)
 
Yes, that's what went wrong. I forgot to put in the initial conditions properly! Thank you.
 

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