Another capacitor Laplace transform problem

Click For Summary

Homework Help Overview

The discussion revolves around a capacitor problem involving the use of Laplace transforms to analyze the voltage across two capacitors discharging and charging through a resistor. Participants are exploring the mathematical setup of coupled differential equations related to this circuit.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to set up a system of equations based on the circuit's behavior but encounters difficulties when applying the Laplace transform. Some participants suggest that the current in the circuit being equal could simplify the equations, while others point out the importance of initial conditions in obtaining non-trivial solutions.

Discussion Status

The discussion is active, with participants offering insights into the setup of the problem and the implications of initial conditions. There is acknowledgment of a mistake regarding the initial conditions, which may have contributed to the challenges faced by the original poster.

Contextual Notes

Participants are considering the implications of initial conditions on the system of equations and the potential impact of the ratio of capacitances on the problem's complexity.

bitrex
Messages
190
Reaction score
0
I'm trying to use the Laplace transform to work out another capacitor problem, the voltage as a function of time on a capacitor that's discharging into another capacitor through a resistor. It's the classic two capacitor problem, but I'd like to actually find an expression for the voltage as a function of time across the capacitor that's discharging and the capacitor that's charging. I've tried setting up a coupled differential equation, like this:

\frac{Vc_1 - Vc_2}{R} = C_2\frac{dV_{C2}}{dt}
\frac{Vc_2 - Vc_1}{R} = C_1\frac{dV_{C1}}{dt}

but of course when I take the Laplace transform and try to solve it algebraically I get a system of equations the equivalent of something like A = 5B and B = 4A, which is useless. Any tips on a better way of setting this up would be appreciated.
 
Physics news on Phys.org
I don't know about the laplace transform, but the current in the circuit is the same. so the right side of both equations is equal. integrate both sides and plug in any initial conditions? the problem maybe has to do with the ratio of capacitances.
 
The only way you could get an homogenous system of equations is by letting the initial conditions (voltage of the capacitors) be zero, then it's not a surprise you will get a trivial solutions.

Use

L(\frac{d}{dt}y)(s)=sY(s)-y(0)
 
Yes, that's what went wrong. I forgot to put in the initial conditions properly! Thank you.
 

Similar threads

Replies
9
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
5
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
Replies
1
Views
2K