you push a 325 newton trunk up a 20 degree inclined plane at a constant velocity by exerting a 211 newton force parallel to the planes surface.
a. what is the component of the trunks weight?
b. what is the sum of all the forces parallel to the planes surface?
c. what are the magnitude and direction of the friction force?
d. what is the coefficient of friction?
The Attempt at a Solution
a. sin 20 = Fx/325 --> Fx = 111.2 N?
b. not quite sure because i dont know if the Fx should be positive or negative.
c. 211 N for magnitude? same for Ff? due to equilibrium?
d. Ff= 111.2, Fn= 305.5, coefficient of friction= ?
--> equation --> Ff= coeff*Fn
--> 111.2= coeff*305.5
--> coeff= 0.36? i think.
im not exactly sure what the 211 force should be labeled as (the stuff in red). i thought i was supposed to be the applied force, but i dont think thats right.
Fn= normal force
Ff= frictional force
Fg= force due to gravity
Fx= x component
Fy= y component