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delecticious
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Another URGENT HELP problem: Steam to Ice
How many J of energy must be removed when 127.0 g of steam, at a temperature of 153.0°C, is cooled and frozen into 127.0 g of ice at 0°C? Take the specific heat of steam to be 2.1 kJ/(kg·K).
Q1 = mc(delta T) <---- c= heat capacity of steam
Q2 = mLv
Q3 = mc(deltaT)<---- c=heat capacity of water
Q4 = mLf
first I converted grams to kilograms and got .127kg for the mass then I follwed through with my equations
Q1 = (.127)(2100)(153-100)= 1.4135E4
Q2 = (.127)(2259.36)= 2.869E2
Q3 = (.127)(4186)(100-0)= 5.316E4
Q4 = 4.241E4
I added these up and got a total Q of 1.10E5, what am I doing wrong?
Homework Statement
How many J of energy must be removed when 127.0 g of steam, at a temperature of 153.0°C, is cooled and frozen into 127.0 g of ice at 0°C? Take the specific heat of steam to be 2.1 kJ/(kg·K).
Homework Equations
Q1 = mc(delta T) <---- c= heat capacity of steam
Q2 = mLv
Q3 = mc(deltaT)<---- c=heat capacity of water
Q4 = mLf
The Attempt at a Solution
first I converted grams to kilograms and got .127kg for the mass then I follwed through with my equations
Q1 = (.127)(2100)(153-100)= 1.4135E4
Q2 = (.127)(2259.36)= 2.869E2
Q3 = (.127)(4186)(100-0)= 5.316E4
Q4 = 4.241E4
I added these up and got a total Q of 1.10E5, what am I doing wrong?