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Homework Statement
If 10-kg of ice at 0 degrees Celsius is added to 2-kg of steam at 100 degrees Celsius, the temperature of the resulting mixture is? Use Joules. ANSWER: 40
Homework Equations
Specific Heats:
Ice = 2060
Steam = 2020
Latent Heats:
Water melting = 3.33x10^5
Water boiling = 2.26x10^6
The Attempt at a Solution
Q1=mL
Q1=10(3.34x10^5)
Q1=3.34x10^6
Q2=(2)(2.26x10^6)
Q2=4.52x10^6
Q2-Q1=1.18x10^6
Q=MCΔT
1.18x10^6 = (2+10)(4180)(T-0)
1.18x10^6 = 5.0x10^4T
T=23.6
Sadly 23.6 =/= 40
I've been trying to do this problem for over an hour now using every method I remember, stumped.