- #26

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so use x = Xo + Voxt + .5at

to find t

by setting Vox 3.60ms

to find t

by setting Vox 3.60ms

- Thread starter hurtingBrain
- Start date

- #26

- 23

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so use x = Xo + Voxt + .5at

to find t

by setting Vox 3.60ms

to find t

by setting Vox 3.60ms

- #27

- 37

- 0

No no no. JoshMP is incorrect. You can find t using your horizontal velocity and displacement.

- #28

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Once you have t, plug it into Yf= Yi +.5(-g)t^2 and solve for Yf.

- #29

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i know that a = -9.8

and t = .5 cuz i did V = t/D

is Xo = o and Vox = 0?

- #30

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That was the question I was answering earlier when I said to use trig. You need to know the y-component to calculate the final velocity. I was not talking about finding t.

- #31

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v = d/t, you've got it the wrong way around.

And no, x = 0. But initial velocity is zero.

And no, x = 0. But initial velocity is zero.

- #32

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joshMp how would you use trig if you only have one number and no degree?

- #33

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- #34

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That was the question I was answering earlier when I said to use trig. You need to know the y-component to calculate the final velocity. I was not talking about finding t.

My apologies, I thought the initial post (the one I've quoted second) was in response to v=d/t.^ You need the final velocity to use that equation. Find the time to reach horizontal displacement, then use that time to find the vertical displacement.

- #35

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i'm confused, so in Vf^2 = Vx^2 + Vy^2

and you said that final is 3.60 m/s than what is Vx?

and you said that final is 3.60 m/s than what is Vx?

- #36

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No. Vx= 3.6 m/s. You need to find Vy before you can find Vfinal.

- #37

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oh, than to find Vy = Voy - at?

- #38

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Yep.

- #39

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than what is the time and Voy

i know that a = -9.8

i know that a = -9.8

- #40

drizzle

Gold Member

- 366

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than what is the time and Voy

i know that a = -9.8

Vo is the initial velocity, you have the initial speed [17.0 m/s] and the angle [35.0° above the horizontal] and a hint:

the sine helps you solve for the vertical component.

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