physicsface
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v = d/t, you've got it the wrong way around.
And no, x = 0. But initial velocity is zero.
And no, x = 0. But initial velocity is zero.
The discussion revolves around two-dimensional motion problems, specifically focusing on projectile motion. The original poster presents a scenario involving a baseball throw and later introduces a swimming scenario involving horizontal motion off a diving board.
Participants are actively engaging with the problems, offering suggestions for using trigonometric functions to find components of velocity. There is a mix of interpretations regarding the application of equations and the roles of horizontal and vertical components in the context of projectile motion. Some guidance has been provided, but no consensus has been reached on all aspects of the problems.
Assumptions include neglecting air resistance in the baseball throw scenario and the need for clarity on the initial conditions and components of motion in both scenarios. There is also a mention of confusion regarding the application of kinematic equations and the use of trigonometry in the absence of angles in the swimming scenario.
JoshMP said:"so would the final velocity be 3.60 m/s"
That was the question I was answering earlier when I said to use trig. You need to know the y-component to calculate the final velocity. I was not talking about finding t.
JoshMP said:^ You need the final velocity to use that equation. Find the time to reach horizontal displacement, then use that time to find the vertical displacement.
hurtingBrain said:than what is the time and Voy
i know that a = -9.8
physicsface said:the sine helps you solve for the vertical component.