Another Two Dimensional motion question

[physicsface]

v = d/t, you've got it the wrong way around.

And no, x = 0. But initial velocity is zero.

 

[hurtingBrain]

joshMp how would you use trig if you only have one number and no degree?

 

[JoshMP]

You have the x component, which was given to you. Find the y component using a kinematic equation. You now have the x component and the y component of the final velocity vector. Vf^2= Vx^2 + Vy^2

 

[physicsface]

"so would the final velocity be 3.60 m/s"

That was the question I was answering earlier when I said to use trig. You need to know the y-component to calculate the final velocity. I was not talking about finding t.

^ You need the final velocity to use that equation. Find the time to reach horizontal displacement, then use that time to find the vertical displacement.

My apologies, I thought the initial post (the one I've quoted second) was in response to v=d/t.

 

[hurtingBrain]

i'm confused, so in Vf^2 = Vx^2 + Vy^2
and you said that final is 3.60 m/s than what is Vx?

 

[JoshMP]

No. Vx= 3.6 m/s. You need to find Vy before you can find Vfinal.

 

[hurtingBrain]

oh, than to find Vy = Voy - at?

 

[JoshMP]

Yep.

 

[hurtingBrain]

than what is the time and Voy
i know that a = -9.8

 

[drizzle]

than what is the time and Voy
i know that a = -9.8

Vo is the initial velocity, you have the initial speed [17.0 m/s] and the angle [35.0° above the horizontal] and a hint:

the sine helps you solve for the vertical component.