Answer: Potential Difference Va-Vb for 4.3 nC Particle in 225 N/C Field

In summary, the conversation discusses a problem regarding a uniform electric field with magnitude 225 N/C directed to the right, a particle with charge +4.3 nC moving from point a to b, and the potential difference between these points. The necessary equations and units are mentioned, and four comments are made regarding the solution. The distance between a and b is stated to be 0.25 m, and the solution is successfully found.
  • #1
phy112
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0

Homework Statement



a uniform electric field has magnitude E = 225 N/C and is directed to the right. A particle with charge +4.3 nC moves along the straight line from a to b.
What is the potential difference Va - Vb between points a and b?

Homework Equations



Potential dif=Va-Vb

The Attempt at a Solution



I found the electric force and the work done on the particle. electric force is .968 and the work done is .242
 
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  • #2
Four comments:

1. We would need to know the distance between a & b, and whether they lie "along" the field line or at some angle to the field, in order to answer the question.

2. You didn't put units with your answers.

3. Are you aware how much a nanoCoulomb is?

4. Electric potential difference can be determined from the work down and the charge.
Hint: units of potential difference are Volts, which are equivalent to Joules per Coulomb.
 
  • #3
the distance is .25 m.
 
  • #4
I figured it out. Thanks a lot!
 

Related to Answer: Potential Difference Va-Vb for 4.3 nC Particle in 225 N/C Field

What is "Potential Difference"?

Potential difference, also known as voltage, is the difference in electric potential between two points in an electric field. It is measured in volts (V).

What is Va-Vb?

Va-Vb represents the potential difference between two points, Va and Vb, in an electric field. It is calculated by subtracting the potential at point Vb from the potential at point Va.

What is a 4.3 nC particle?

A 4.3 nC particle refers to a particle with a charge of 4.3 nanocoulombs (nC). Coulombs is the unit of electric charge, and 1 nC is equivalent to 1 billionth of a coulomb.

What does the 225 N/C field represent?

The 225 N/C field represents the strength of the electric field at a certain point. It is measured in newtons per coulomb (N/C) and indicates the force that would be exerted on a charge placed in that field.

How is the potential difference calculated for a particle in an electric field?

The potential difference for a particle in an electric field can be calculated using the formula V = Ed, where V is the potential difference, E is the electric field strength, and d is the distance between the two points in the field. The potential difference is directly proportional to the electric field strength and the distance between the points.

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