Answer: Potential Difference Va-Vb for 4.3 nC Particle in 225 N/C Field

[phy112]

Homework Statement

a uniform electric field has magnitude E = 225 N/C and is directed to the right. A particle with charge +4.3 nC moves along the straight line from a to b.
What is the potential difference Va - Vb between points a and b?

Homework Equations

Potential dif=Va-Vb

The Attempt at a Solution

I found the electric force and the work done on the particle. electric force is .968 and the work done is .242

 

[Redbelly98]

Four comments:

1. We would need to know the distance between a & b, and whether they lie "along" the field line or at some angle to the field, in order to answer the question.

2. You didn't put units with your answers.

3. Are you aware how much a nanoCoulomb is?

4. Electric potential difference can be determined from the work down and the charge.
Hint: units of potential difference are Volts, which are equivalent to Joules per Coulomb.

 

[phy112]

the distance is .25 m.

 

[phy112]

I figured it out. Thanks a lot!