Answer: Solving Torque Problems: Shaft Diameter & Stress

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SUMMARY

The discussion focuses on calculating the maximum permissible torque and the angle of twist for a steel shaft used in a socket wrench. Given the shaft's diameter of 18mm and length of 450mm, with an allowable shear stress of 70 MN/m² and a modulus of rigidity (G) of 80 GN/m², the necessary formulas involve the relationship between torque (T), polar second moment of area (J), shear stress (τ), radius (R), and angle of twist (θ). Participants seek clarity on applying these equations to derive the maximum torque and the corresponding angles of twist in both radians and degrees.

PREREQUISITES
  • Understanding of shear stress and its units (MN/m²)
  • Familiarity with the polar second moment of area (J) for circular shafts
  • Knowledge of modulus of rigidity (G) and its significance in torsion
  • Ability to convert between radians and degrees
NEXT STEPS
  • Calculate the polar second moment of area (J) for a circular shaft with a diameter of 18mm
  • Derive the maximum torque (T) using the formula T = τ * J/R
  • Determine the angle of twist (θ) in radians using the formula θ = TL/(GJ)
  • Convert the angle of twist from radians to degrees for practical applications
USEFUL FOR

Mechanical engineers, students studying mechanics of materials, and professionals involved in the design and analysis of rotating shafts will benefit from this discussion.

confusedkarl
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1. Homework Statement

The steel shaft of a socket wrench is 18mm diameter and 450mm long. If the allowable shear stree is 70 MN/m^2.

2. Homework Equations
i) What is the maximum permissible torque T that may be extered with the wrench?
ii) Through what angle (theta) in radians will the shaft twist under the action of the maximum torque?
iii) Through what angle (theta) in degrees will the shaft twist under the action of the maximum torque? G = 80 GN/m^2


3. The Attempt at a Solution

Im pretty happy how to do the radians to degress conversion but haven't a clue on the forumulae or process I need for i and ii =(
 
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For a shaft of uniform cross section:

\frac{T}{J} = \frac{\tau}{R} = \frac{G \theta}{l}

Where T is torque applied, J is the polar second moment of area, Tau is shear stress, R is radius, G is modulus of rigidity, and Theta the angle of twist. All SI units.
 
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