Answer: The mass of the piston is 16.2 kg.Weight of a Piston: 16.2 kg

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SUMMARY

The mass of the piston in a vertical cylindrical tank containing 1.80 mol of an ideal gas at a pressure of 1.05 atm and a temperature of 22.0°C is calculated to be 16.2 kg. This calculation utilizes the ideal gas law equation, pV=nRT, where the pressure, volume, and temperature of the gas are considered. The piston operates without friction, allowing for a straightforward determination of its mass based on the gas pressure and the area of the tank's cross-section.

PREREQUISITES
  • Understanding of the ideal gas law (pV=nRT)
  • Basic knowledge of pressure and force calculations
  • Familiarity with unit conversions (atm to kg)
  • Concept of frictionless systems in physics
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  • Study the ideal gas law applications in real-world scenarios
  • Learn about pressure calculations in fluid mechanics
  • Explore the concept of frictionless motion in physics
  • Investigate the relationship between gas properties and piston dynamics
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Students in physics or engineering, particularly those studying thermodynamics and fluid mechanics, will benefit from this discussion. It is also useful for anyone interested in understanding the principles behind gas behavior in confined spaces.

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Homework Statement



A vertical cylindrical tank contains 1.80 mol of an ideal gas under a pressure of 1.05 atm at 22.0[tex]^\circ[/tex] C. The round part of the tank has a radius of 10.0 cm , and the gas is supporting a piston that can move up and down in the cylinder without friction.

What is the mass of this piston?

Homework Equations



pV=nRT

The Attempt at a Solution



[tex].05*1 \; atm*.01\pi \: m^2/9.8 \approx 16.2 kg[/tex]
 
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james brug said:

Homework Statement



A vertical cylindrical tank contains 1.80 mol of an ideal gas under a pressure of 1.05 atm at 22.0[tex]^\circ[/tex] C. The round part of the tank has a radius of 10.0 cm , and the gas is supporting a piston that can move up and down in the cylinder without friction.

What is the mass of this piston?

Homework Equations



pV=nRT

The Attempt at a Solution



[tex].05*1 \; atm*.01\pi \: m^2/9.8 \approx 16.2 kg[/tex]
What determines the pressure of the gas in the cylinder? How much of that force (per unit area) is due to the weight of the pistion?

AM
 

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