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**Question**

f'(x) = 1.4x*cos(x^1.9)

Find f(x)

**Attempt**

Ok, first of all, I'm really bad at Calculus, so bear with me >__<

I figured to find the antiderivative of the thing is equivalent to

[tex]\int\left1.4x*cos\leftx^{1.9}\right\right)dx[/tex]

I've tried simple substitution (u = x^1.9) and that obviously doesn't work, and I tried integration by parts, but I don't think it's working

If I had dv = cos(x^1.9)dx

I'm unsure if I can find v when x is x^1.9

Help will be appreciated! Thanks!

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