# How do I set this antiderivative up?

Mod note: Moved from technical math section, so there's no template.
Sorry if I'm formatting this question wrong, new user.
I tried to set up the antiderivative as (2/3)(x^3+x+1)^(3/2) and then plugging 1 in to get -2.125, but its clearly wrong. Is there another step I need to do?

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posted in the wrong place sorry thought this was the homework forum. how do i delete post?

Mark44
Mentor
Sorry if I'm formatting this question wrong, new user.
I tried to set up the antiderivative as (2/3)(x^3+x+1)^(3/2)
No, that isn't right, assuming that the integrand is ##\sqrt{x^3 + x + 1}##. If you differentiate your proposed antiderivative, you don't get ##\sqrt{x^3 + x + 1}##.
jakka said:
and then plugging 1 in to get -2.125, but its clearly wrong. Is there another step I need to do?

Are you sure you have copied the problem correctly? As written this is not a simple integration problem.

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Ray Vickson
Homework Helper
Dearly Missed
Mod note: Moved from technical math section, so there's no template.
Sorry if I'm formatting this question wrong, new user.