Antiderivative of 1/((x(lnx)^3) using u-substitution

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Homework Help Overview

The original poster is working on finding the antiderivative of the function 1/((x(lnx)^3), which involves the use of u-substitution where u = lnx. The problem is situated within the context of calculus, specifically focusing on integration techniques.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the appropriate substitution and the transformation of the integrand in terms of u. There are questions regarding the correct expression for x in terms of u and the proper substitution for dx. Some participants express confusion about handling the third power in the antiderivative.

Discussion Status

The discussion is ongoing, with participants providing guidance on the substitution process and clarifying the transformation of the integrand. There is recognition of the need to correctly handle the powers involved in the integration, and some participants are exploring the implications of their findings.

Contextual Notes

There is a focus on ensuring all components of the integral are correctly transformed during the substitution process. Participants are navigating the complexities introduced by the third power in the integrand.

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Homework Statement


I'm working on an infinite series problem and need to find the antiderivative of 1/((x(lnx)^3).


Homework Equations


u=lnx


The Attempt at a Solution


I know I have to use the substitution u=lnx, but I still can't figure out what the answer is. I know the antiderivative of 1/((x(lnx)) is ln(lnx) but the third power in my problem is giving me trouble. Any advice? Thanks!
 
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After the u-substitution, what is the integrand in terms of u now?
 
It would be 1/(x(u)^3)
 
stau40 said:
It would be 1/(x(u)^3)
When you make a substitution, replace everything. Here you still have a factor of x remaining. If u = ln(x), what is x in terms of u? Also, and this is related, did you replace dx by its appropriate expression involving du?
 
Ok, it should be the antiderivative of du/(u^3) but I still don't understand how to work thru the third power. If I solve for the antiderivative and end up with u^4 I would need (1/4) in front of u and that gets me to the wrong result.
 
stau40 said:
Ok, it should be the antiderivative of du/(u^3) but I still don't understand how to work thru the third power. If I solve for the antiderivative and end up with u^4 I would need (1/4) in front of u and that gets me to the wrong result.

Well, yes. You can't go from du/u^3 to u^4.

du/u^3 = u^(-3)du
 
The light finally came on, Thanks!
 

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