Antisymmetric and symmetric part of a general tensor

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SUMMARY

A general covariant or contravariant tensor of rank n can be expressed as the sum of its symmetric and antisymmetric parts, represented as T^{\mu_1 \ldots \mu_n} = T^{[\mu_1 \ldots \mu_n]} + T^{(\mu_1 \ldots \mu_n)}. This decomposition is valid for rank 2 tensors, but for rank 3 and higher, the tensor can be separated into totally symmetric and totally antisymmetric components, with additional components exhibiting mixed symmetry. The existence of these mixed symmetry components arises from the discrepancy in the count of independent components between the symmetric and antisymmetric parts and the total components of the tensor.

PREREQUISITES
  • Understanding of tensor notation and rank
  • Familiarity with symmetric and antisymmetric properties of tensors
  • Knowledge of independent component counting in tensor analysis
  • Basic principles of general relativity and tensor calculus
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  • Study the decomposition of tensors in detail, focusing on symmetric and antisymmetric parts
  • Learn about mixed symmetry tensors and their implications in physics
  • Explore the properties of tensors in general relativity, particularly in the context of curvature
  • Investigate the mathematical proofs for tensor component counting and decomposition
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Mathematicians, physicists, and students of general relativity who seek to deepen their understanding of tensor decomposition and its applications in theoretical physics.

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I've seen it stated several times that a general covariant or contravariant tensor of rank n can be separated into it's symmetic and antisymmetric parts

[tex]T^{\mu_1 \ldots \mu_n} = T^{[\mu_1 \ldots \mu_n]} + T^{(\mu_1 \ldots \mu_n)}[/tex]

and this is easy to prove for the case n=2, but I don't see how to prove it for a general n. Could anyone help me out?(suspect this has been posted in the wrong forum, but I also suspect that the general relativists can answer this question as good or better than the mathematicians)
 
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You're right, this statement holds only for two indices. For three or more you can separate the totally symmetric part and the totally antisymmetric part, but there's leftovers. This is easy to confirm just by counting up the independent components of the symmetric and antisymmetric parts and seeing that they don't add up to the expected total. We say the leftover part has "mixed" symmetry.
 

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