- #1
- 6
- 0
Any point in 3-dimensional space
Is is possible to write any point [tex] {\bf x}\in \mathbb{R}^{3}[/tex] as a linear combination of vectors [tex]{\bf v_{j}}[/tex] inside the unit ball over [tex]\mathbb{R}[/tex] given that
[tex]\sum_{j}c_{j}{\bf v_{j}}[/tex]
can be made arbitrarily small?
My approach was letting
[tex] \parallel{\bf x}\parallel \leq \bigg{\parallel} \sum_{j}c_{j}{\bf v_{j}}\bigg\parallel (*)[/tex]
Then applying the triangle inequality to the two terms then (*), the triangle inequality again to the linear combination, [tex] \parallel v_{j}\parallel<1 [/tex] for all [tex]n[/tex] then the Cauchy's inequality to obtain
[tex] \parallel{\bf x} - \sum_{j}c_{j}{\bf v_{j}}\bigg\parallel [/tex]
[tex] \leq 4n\sum_{j}|c_{j}|^{2} [/tex]
where n is the number of terms in the linear combination, which is finite.
Therefore by letting [tex] \sum_{j}|c_{j}|^{2} \rightarrow 0[/tex],
we get
[tex]\parallel{\bf x}- \sum_{j}c_{j}{\bf v_{j}}\bigg\parallel \leq 0 [/tex]
Thus deducing
[tex] {\bf x} = \sum_{j}c_{j}{\bf v_{j}} [/tex]
I am not sure if assuming (*) is the correct way of doing this since we miss out on the other possibility (>).
Is is possible to write any point [tex] {\bf x}\in \mathbb{R}^{3}[/tex] as a linear combination of vectors [tex]{\bf v_{j}}[/tex] inside the unit ball over [tex]\mathbb{R}[/tex] given that
[tex]\sum_{j}c_{j}{\bf v_{j}}[/tex]
can be made arbitrarily small?
My approach was letting
[tex] \parallel{\bf x}\parallel \leq \bigg{\parallel} \sum_{j}c_{j}{\bf v_{j}}\bigg\parallel (*)[/tex]
Then applying the triangle inequality to the two terms then (*), the triangle inequality again to the linear combination, [tex] \parallel v_{j}\parallel<1 [/tex] for all [tex]n[/tex] then the Cauchy's inequality to obtain
[tex] \parallel{\bf x} - \sum_{j}c_{j}{\bf v_{j}}\bigg\parallel [/tex]
[tex] \leq 4n\sum_{j}|c_{j}|^{2} [/tex]
where n is the number of terms in the linear combination, which is finite.
Therefore by letting [tex] \sum_{j}|c_{j}|^{2} \rightarrow 0[/tex],
we get
[tex]\parallel{\bf x}- \sum_{j}c_{j}{\bf v_{j}}\bigg\parallel \leq 0 [/tex]
Thus deducing
[tex] {\bf x} = \sum_{j}c_{j}{\bf v_{j}} [/tex]
I am not sure if assuming (*) is the correct way of doing this since we miss out on the other possibility (>).
Last edited: