AP Physics ~ A good jump in the long jump event is

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SUMMARY

A good jump in the long jump event is determined to be 3.7 meters, requiring a takeoff speed of 13.1 m/s at an angle of 25°. The calculation utilizes the kinematic equation vf² = vi² + 2aY, where vf is the final velocity, vi is the initial velocity, a is the acceleration due to gravity (-9.8 m/s²), and Y is the vertical distance (3.7 m). The discussion emphasizes the importance of posting homework questions in the designated forum section for better assistance.

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  • Understanding of kinematic equations in physics
  • Knowledge of projectile motion principles
  • Familiarity with trigonometric functions, specifically sine
  • Basic grasp of gravitational acceleration (9.8 m/s²)
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  • Study the application of kinematic equations in projectile motion
  • Learn how to derive initial velocity from final distance and angle
  • Explore the effects of different angles on jump distances
  • Investigate real-world factors affecting long jump performance
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A good jump in the long jump event is 3.7m. If the jumper leaves the ground at an angle of 25°, what speed must he need to jump the 3.70m distance?

→Could you use this equation: vf²=vi²+2aY aka (final velocity)²= (initial velocity)²+2(acceleration)(distance in the y-direction)
→So, that would be: 0=(vsin25 °)²+2(-9.8)(3.7)∴ v=13.1m/s

Please help me if I am wrong.
 
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