AP Physics C Mechanics: Linear Momentum for Colliding Billiard Balls

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SUMMARY

The discussion focuses on solving a physics problem involving the conservation of momentum for colliding billiard balls. The initial velocity (Vi) of the first ball is given as 5 m/s, and the final velocity of the second ball is noted as 4.35 m/s. Participants emphasize the need to set up two equations based on momentum conservation in both x and y directions to solve for the unknowns: the final velocity (V) of the first ball and the angle (θ) of deflection. The approach involves using algebraic methods to isolate these variables for clarity and troubleshooting.

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  • Familiarity with vector components in physics
  • Basic algebra for solving equations
  • Knowledge of trigonometric functions (sine and cosine)
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  • Learn how to resolve vectors into their components
  • Practice solving simultaneous equations in physics problems
  • Explore the application of trigonometry in physics, particularly in collision scenarios
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Daniel Guh
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Homework Statement
A billiard ball moving at 5 m/s strikes a stationary ball of the same mass. after the collision, the original ball moves at a velocity of 4.35 m/s at an angle of 30° below its original motion. find the velocity and angle of the second ball after the collision.
Relevant Equations
Pi = Pf
P = mv
I'm guessing this question can be solved using the law of conservation of momentum
Vi = 5 m/s

(5 m/s) M = (4.33 m/s) cos30 M + V sinθ M

I don't know what to do after this... I'm also not sure if I use the sin and cos correctly.
 
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Assuming planar motion, you want to look at conservation of momentum in each direction. I believe that will give you two equations two unknowns i.e. the velocity of the initially stationary ball after collision, and the mass of the billiard balls.

Edit: I guess you aren’t after the mass (couldn’t solve for it anyway). Either way two equations two unknowns to find the angle.
 
Last edited:
So momentum in the y direction should cancel out?
4.33 M sin30 = MV sin θ
And the momentum in the x direction will equal the original momentum so
5M = 4.33 M cos30 + MV cosθ
 
Yeah, but remember you are going to find the component of the second balls velocity in each direction.

Edit: I guess you can have the unknown angle in those equations, but I wouldn’t bother in this step. I would just find ##v_x## and ##v_y##. Then get the angle from their ratio. Up to you though.

Also, the question says ##4.35~ \rm {m/s}## not ##4.33##. Which is it?
 
Last edited:
Daniel Guh said:
So momentum in the y direction should cancel out?
4.33 M sin30 = MV sin θ
And the momentum in the x direction will equal the original momentum so
5M = 4.33 M cos30 + MV cosθ
That looks OK. You have two equations and two unknowns, V and θ. How are you going to extract them from the equations?

I would use V0 for the initial speed of the first ball, V1 for the final speed of the first ball and V2 for the final speed of the target ball. I would then find V2 and θ algebraically and substitute numbers at the very end. The algebra is easier to troubleshoot that way, for you and for us.
 
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