AP Physics C Mechanics: Linear Momentum for Colliding Billiard Balls

AI Thread Summary
The discussion focuses on solving a physics problem involving the conservation of momentum in a collision between billiard balls. Participants emphasize the importance of breaking down the momentum equations into x and y components to find the unknowns, specifically the final velocity of the stationary ball and the angle of deflection. There is some confusion regarding the correct speed values, with a correction noted from 4.33 m/s to 4.35 m/s. It is suggested to use algebraic methods to isolate the variables for easier troubleshooting. Overall, the conversation underscores the necessity of applying conservation laws accurately in two-dimensional motion scenarios.
Daniel Guh
Messages
4
Reaction score
1
Homework Statement
A billiard ball moving at 5 m/s strikes a stationary ball of the same mass. after the collision, the original ball moves at a velocity of 4.35 m/s at an angle of 30° below its original motion. find the velocity and angle of the second ball after the collision.
Relevant Equations
Pi = Pf
P = mv
I'm guessing this question can be solved using the law of conservation of momentum
Vi = 5 m/s

(5 m/s) M = (4.33 m/s) cos30 M + V sinθ M

I don't know what to do after this... I'm also not sure if I use the sin and cos correctly.
 
Physics news on Phys.org
Assuming planar motion, you want to look at conservation of momentum in each direction. I believe that will give you two equations two unknowns i.e. the velocity of the initially stationary ball after collision, and the mass of the billiard balls.

Edit: I guess you aren’t after the mass (couldn’t solve for it anyway). Either way two equations two unknowns to find the angle.
 
Last edited:
So momentum in the y direction should cancel out?
4.33 M sin30 = MV sin θ
And the momentum in the x direction will equal the original momentum so
5M = 4.33 M cos30 + MV cosθ
 
Yeah, but remember you are going to find the component of the second balls velocity in each direction.

Edit: I guess you can have the unknown angle in those equations, but I wouldn’t bother in this step. I would just find ##v_x## and ##v_y##. Then get the angle from their ratio. Up to you though.

Also, the question says ##4.35~ \rm {m/s}## not ##4.33##. Which is it?
 
Last edited:
Daniel Guh said:
So momentum in the y direction should cancel out?
4.33 M sin30 = MV sin θ
And the momentum in the x direction will equal the original momentum so
5M = 4.33 M cos30 + MV cosθ
That looks OK. You have two equations and two unknowns, V and θ. How are you going to extract them from the equations?

I would use V0 for the initial speed of the first ball, V1 for the final speed of the first ball and V2 for the final speed of the target ball. I would then find V2 and θ algebraically and substitute numbers at the very end. The algebra is easier to troubleshoot that way, for you and for us.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Trying to understand the logic behind adding vectors with an angle between them'
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
Back
Top