AP Physics: Momentum Change Calculated for Dropped Ball

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SUMMARY

The discussion focuses on calculating the change in momentum for a 3.0-kg ball dropped from a height, which strikes the ground at a velocity of 16.0 m/s and rebounds at -12.0 m/s. The change in momentum is determined using the formula p = mv, where the final momentum is calculated as p_final = m * v_final and the initial momentum as p_initial = m * v_initial. The change in momentum is thus Δp = p_final - p_initial, highlighting the significance of direction in vector quantities.

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  • Understanding of momentum and its formula (p = mv)
  • Knowledge of vector quantities and their properties
  • Basic physics concepts related to motion and forces
  • Ability to perform calculations involving mass and velocity
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A 3.0-kg ball, which is dropped, strikes the ground with a velocity of 16.0 m/s and rebounds with a velocity of -12.0 m/s. What is the change in momentum?
 
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Remember the formula for momentum?
 


p=mv ?
 


Yes. Now how does that apply to the problem? If p = mv, what is change in p?
 


mv final-mv inital
 


Yep. Now is momentum a vector quantity? Does the sign matter?
 

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