AP Physics problem help - centripetal motion

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Homework Help Overview

The problem involves a suitcase on a baggage carousel, moving in a circular path with a specified radius and angle. Participants are exploring concepts related to centripetal motion and the forces acting on the suitcase, including friction and gravitational components.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to analyze the forces acting on the suitcase, including friction and gravitational forces. There are discussions about the net force and the components of forces involved in circular motion. Some participants express confusion about their calculations and seek clarification on the relationships between variables.

Discussion Status

Several participants have shared their calculations and reasoning but express uncertainty about the correctness of their answers. There is a mix of attempts to derive equations and check assumptions, with some participants asking for hints or confirmations of their understanding. No consensus has been reached on the solution, and multiple interpretations of the problem are being explored.

Contextual Notes

Some participants mention variations in parameters, such as radius and angle, which may affect their approaches. There is also a reference to a specific textbook and a provided equation from a teacher, indicating reliance on course materials for guidance.

stuplato
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This problem is KILLING ME!
The drawing shows a baggage carousel at an airport. Your suitcase has not slid all the way down the slope and is going around at a constant speed on a circle (r = 10.8 m) as the carousel turns. The coefficient of static friction between the suitcase and the carousel is 0.760, and the angle in the drawing is 35.6°. How much time is required for your suitcase to go around once?
05_26.gif

Please help!
It involves centripetal motion
 

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So far here is what I got:

Fc = m*g*tan(theta)
Fn = m*g*cos(theta)
Ffrx (this is x-component of friction) = m*g*cos(theta)*cos(theta)

Ffrx + Fc = (m*w^2) / r

But the answer I get is wrong!
 
What is the net force acting on the bag? Redo your force diagram.
 
whozum said:
What is the net force acting on the bag? Redo your force diagram.
Net force is opposite of the perpendicular component of gravity which will be mass times g times cos(theta)
So... Fn = m times 7.968
And Friction will be u times Fn...
Ffr = m times 6.056
And Fc is m times .7159
The x component of Friction will be cos(theta) times Ffr
Ffrx = m times 4.924
And using Ffrx + Fc = (m*w^2) / r
m*4.924+m*.7159 = m*w^2) / r
the mass cancels out and i get
5.64 = w^2 / 10.8
Simplify...
w = .725
Now w = C/T and C= 2*pi*r
.725 / T = 2*pi*10.8
T = .0107
 
This is still wrong :cry:
 
Haha we have that exact same drawing/diagram in our book...you got the book with the skier on it?
 
I know T must be atleast twenty, but I just cannot get it, please give me a hint!
 
celticsthree4 said:
Haha we have that exact same drawing/diagram in our book...you got the book with the skier on it?

Ya, Cutnell 5th edition
 
Let me try this:
w = .725 & C = 21.6*pi
21.6*pi = .725*t
And I get 93.598 for t... somehow that sounds high, but I like someone 2 double check me please
 
  • #10
stuplato said:
Let me try this:
w = .725 & C = 21.6*pi
21.6*pi = .725*t
And I get 93.598 for t... somehow that sounds high, but I like someone 2 double check me please

It's wrong AGAIN :cry:
 
  • #11
Answer this question: What forces act on the suitcase? (I see three forces.)

Then answer this: What is the net centripetal force?

Answer these questions with symbols, not numbers.
 
  • #12
i'm struggling with this same problem except my numbers are a little different my r=11.4, friction is .76 and theta as 36.8.
To be completely honest I am in Physics 1 and have no idea how to do physics at all. I understand the concepts, but have a really hard time finding the right equations and right times to use those equations.
I know there are three forces that are acting on it you got the force from the friction pointing up, you have mg acting on the suitcase downwards and you have the N force pulling from the center towards the suitcase.
 
  • #13
My teacher in class gave us this equation to solve for the problem:
T= 2 pi sqrt. (R/g)(usin theta +cos theta / ucos theta - sin theta)

I'm not really sure what u= if i knew i think i could solve the problem.
Just to confirm
g=9.8 m/s^2
R=11.4

right?
 

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