AP Physics Summer work problems

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Homework Help Overview

The discussion revolves around a physics problem involving a bow that behaves like a spring, specifically focusing on calculating the work done when drawing the bow and determining the speed of an arrow upon release. The subject area includes concepts from mechanics, particularly spring potential energy and work-energy principles.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the work equation and the potential energy formula for springs. There are attempts to clarify the relationship between work done and potential energy, with some participants questioning the correct use of formulas.

Discussion Status

Some participants have provided guidance on the correct equations to use, while others are exploring different interpretations of the problem. The discussion reflects a mix of understanding and confusion, particularly regarding the conversion of potential energy to work done and the subsequent calculation of the arrow's speed.

Contextual Notes

One participant notes their lack of prior physics knowledge, which may influence their understanding of the concepts being discussed. There is also mention of a second part to the problem that requires finding the speed of the arrow, indicating a multi-step nature to the homework assignment.

Iamaskier721
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Homework Statement



Assuming you have a bow that behaves like a spring with a spring constant of 168 N/m and you pull it to a draw of 54 cm, to the nearest joule how much work do you perform?

Homework Equations



The force of a constant spring is f=-k(x) where x is the displacement and k is the spring constant.

The Attempt at a Solution



So Basically If I find the force and then place it into the simple work equation W=F(x) where x is displacement and F is force. I get 49(rounded). Am I doing this correctly?
 
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There's an equation for potential spring energy... it looks similar to the kinetic energy equation, but with different variables.
 
Welcome to the forums Iammaskier,

Yes, it looks like you are doing it correctly to me. Basically, W = k*x^2 in this case.

There's an equation for potential spring energy... it looks similar to the kinetic energy equation, but with different variables.

Ok, but what does that have to do with this problem?
 
Is use that equation of u=1/2kx^2 and got 24.4944 joules. How does that convert to the work performed?
 
Another quick question! There is a second part which is... to the nearest tenth of a m/s, what is the speed of the 98 gram arrow when it is released?

I know I have to find the velocity but I have no clue how to do it.


I've never taken physics before and it's decenlty hard to teach yourself=/
 
This link shall explain why you simply can't use W=kx^2, but instead W=.5kx^2

http://inventors.about.com/gi/dynamic/offsite.htm?site=http://www.emporia.edu/physics/keithron/collegelab1/hooklaw.htm
 
Last edited by a moderator:
And of course, once you realize that, then the second part to your problem should become quite easy if you understand the conservation of energy, as well as a comparison I made in my initial reply regarding another similar looking equation.
 

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