Apparent disagreement between Coulomb's Law and Gauss' Law

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SUMMARY

The discussion centers on the apparent discrepancy between Coulomb's Law and Gauss's Law when calculating the electric field at point P, located equidistant from two point charges, +Q and -Q. Using Coulomb's Law, the electric field is calculated as E=(1/2πε0)Q/r², while Gauss's Law yields E=(1/4πε0)Q/r². The key error identified is the assumption of symmetry in the Gaussian surface, which does not hold true for the total electric field at point P. A proper integral calculation is necessary to resolve the inconsistency.

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shj
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This is probably my misunderstanding, so please clarify.

In a region of empty space, there are two point charges with the charges+Q and -Q. Exactly in the middle of the two charges (distance r from both charges) is point P, colinear with the centers of both charges. A Gaussian surface that includes point P is drawn above.

Using Coulomb's Law, we can find the electric field at point P:
E=2*((1/4πε0)Q/r2)=(1/2πε0)Q/r2)
(since the electric field vectors caused by both charges have the same magnitude and add at point P)

However, if I try to use Gauss's Law to calculate the electric field at point P, I get:
E*4πr2=Qenclosed0, or
E=(1/4πε0)Q/r2)
(since the Gaussian surface is symmetric to the electric field, I simplified the surface integral to E*4πr2)

The two calculations differ! Can someone please clarify the error?!
 

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Simple. The total field is not constant across the Gauss surface. You would really need to do the integral.

In other words, here is your error:
shj said:
(since the Gaussian surface is symmetric to the electric field, I simplified the surface integral to E*4πr2)
Not symmetric for the total field!

Note: Welcome to PF!
 
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Stavros Kiri said:
Simple. The total field is not constant across the Gauss surface. You would really need to do the integral.

In other words, here is your error:

Not symmetric for the total field!

Note: Welcome to PF!
Oh alright. Thank you.
 
shj said:
Oh alright. Thank you.
You're welcome!
 
shj said:
since the Gaussian surface is symmetric to the electric field,
The electric field is not spherically symmetric

Edit: oops, I am too late. Good job @Stavros Kiri
 
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