Application of vector - answer checking

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SUMMARY

The discussion centers on the calculation of the direction of velocity of ship B relative to ship A, based on their positions and bearings at two different times. At 10:00 AM, ship B is 8 nautical miles from ship A at a bearing of 315°, and at 10:15 AM, it is 6 nautical miles away at a bearing of 320°. The correct answer for the direction of velocity B relative to A is E30.5°S, confirming that the initial response of W30.5°N was incorrect.

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  • Familiarity with bearings and relative positioning
  • Knowledge of nautical miles as a unit of distance
  • Basic principles of constant velocity motion
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Homework Statement



Two ships, A and B are sailing along straight routes with constant velocities. At 10 o clock morning, ship B is 8 nautical miles from A and its bearing from A is 315°. At 10.15 in the morning, ship B is 6 nautical miles from A and its bearing from A is 320°. Find the direction of velocity B relative to A.

Homework Equations





The Attempt at a Solution



My answer: W30.5°N, but answer given if E30.5°S, what answer do you guys get? :smile:
 
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The given answer, E30.5S is correct. How did you get "W... S"?
 

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