Applications of Magnetic Fields

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SUMMARY

The discussion centers on the behavior of an ion with a charge of +1e in a region with an electric field of 630V and a magnetic field of 450mT. The ion moves in a straight line due to the cancellation of the electric and magnetic forces, which occurs only for particles with a specific velocity. This scenario illustrates the function of a velocity selector rather than a mass spectrometer. Key equations involved include the Lorentz force and Ampere's Law.

PREREQUISITES
  • Understanding of the Lorentz force and its components
  • Familiarity with electric fields and magnetic fields
  • Knowledge of velocity selectors and their applications
  • Basic principles of charged particle motion in electromagnetic fields
NEXT STEPS
  • Study the Lorentz force in detail to understand its implications on charged particles
  • Research the principles and applications of velocity selectors in physics
  • Explore the differences between mass spectrometers and velocity selectors
  • Learn about the calculations involved in determining the speed of charged particles in electric and magnetic fields
USEFUL FOR

Students and educators in physics, particularly those focusing on electromagnetism and charged particle dynamics, as well as professionals working with particle accelerators or mass spectrometry.

stonecoldgen
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Homework Statement


An ion with a charge of +1e enters a region where the electric field produced by parallel plates at 630V separated by 7.0mm is at right angles ot a magnetic field B=450mT. The ion moves a straight line. Find the magnitude of the electric field and the speed of the ion.


Homework Equations


F=qvB
Ampere's Law B=μ0I/2∏r



The Attempt at a Solution


Is this a mass spectrometer?

first of all, because the plates are parellel the force is maximized (sin90=1)

I am confused, isn't the ion supposed to curve in a radius defined by: r=mv/qB (mv2/r=qvB)

I just don't know what to do since the ion doesn't curve.

Thanks.
 
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stonecoldgen said:

Homework Statement


An ion with a charge of +1e enters a region where the electric field produced by parallel plates at 630V separated by 7.0mm is at right angles ot a magnetic field B=450mT. The ion moves a straight line. Find the magnitude of the electric field and the speed of the ion.

Homework Equations


F=qvB
Ampere's Law B=μ0I/2∏r

The Attempt at a Solution


Is this a mass spectrometer?

first of all, because the plates are parellel the force is maximized (sin90=1)

I am confused, isn't the ion supposed to curve in a radius defined by: r=mv/qB (mv2/r=qvB)

I just don't know what to do since the ion doesn't curve.

Thanks.

A moving charge in a magnetic field curves because the Lorentz force acts as a centripetal force. In this case the fields are arranged in such a way that the electric force cancels the magnetic force, so the path never bends. But since the force on the moving charge depends upon its velocity, this cancellation will occur only for same-charge particles with a specific velocity.

It's not a mass spectrometer; it behaves as a velocity selector.
 
sorry, can you please tell me how to work with velocity selectors? thanks I really appreciate it
 
stonecoldgen said:
sorry, can you please tell me how to work with velocity selectors? thanks I really appreciate it

Look up the Lorentz Force. It's comprised of the sum of the forces on charge due to electric and magnetic fields. In this problem you're told that the particle moves in a straight line at some velocity v, so what's the net force?
 

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