Apply the law of conservation of energy to determine the ball's speed

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SUMMARY

The discussion focuses on applying the law of conservation of energy to calculate the speed of a 0.20-kg ball dropped from a height of 2.2 m. The ball's speed is determined to be 4.6 m/s after falling 1.1 m and 6.6 m/s after falling the full 2.2 m. The calculations utilize the formulas for gravitational potential energy and kinetic energy, confirming the principles of energy conservation in a frictionless environment.

PREREQUISITES
  • Understanding of gravitational potential energy formula (PE = mgh)
  • Knowledge of kinetic energy formula (KE = 0.5mv²)
  • Basic principles of the law of conservation of energy
  • Familiarity with units of measurement in physics (meters, kilograms, seconds)
NEXT STEPS
  • Study the derivation of the gravitational potential energy formula
  • Explore the relationship between potential energy and kinetic energy in various scenarios
  • Learn about energy conservation in different physical systems
  • Investigate the effects of air resistance on falling objects
USEFUL FOR

Students studying physics, educators teaching energy concepts, and anyone interested in understanding the mechanics of motion and energy conservation.

Nicholasw
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What formula would I use to solve for a and b?

A 0.20-kg ball is held at rest 2.2 m above the ground, and then it is dropped. Apply the law of conservation of energy to determine the ball's speed after it has fallen (a) 1.1 m and (b) 2.2 m. Ignore air resistance.

Answers
(a) 4.6 m/s
(b) 6.6 m/s

So How would I get these answers?

Thanks
 
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You use two formulas; the one ofr gravitational potential energy and the one for kinetic energy.
 
Okay Thanks. I will do that
 

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