- #1
antrobot
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Homework Statement
A new particle with the mass of 317 GeV and natural width which is much smaller than the mass resolution of the detector is under investigation. It decays into two photons with equal energies, which are detected in the electromagnetic calorimeter. If one searches the particle over a range of 50 GeV to 600 GeV, would a bin size of 30 GeV be appropriate? If yes, why? If no, which bin size would you suggest?
Homework Equations
resolution of the calorimeter
[tex] \frac{σ(E)}{E} = \sqrt{(0.1^2 / E + 0.02^2)} [/tex]
The Attempt at a Solution
I have calculated the resolution, using E = m/2 = 317/2 from the photons:
[tex] \frac{σ(E)}{E} = \sqrt{(0.1^2 / 317/2 + 0.02^2)} = 0.0215 => 2.15\% [/tex]
From here I'm not sure how to proceed. If I multiply by the energy of the particle I would get [tex] σ(E) = 0.015 \cdot 317 GeV = 6.8 GeV[/tex]. I would argue that 30 GeV is quite wide based on the resolution 6.8, but still ok, but I'm not even sure if what I'm doing is correct. Thank you for your help in advance!