Approximating solutions on non-rectangular domains

  • Thread starter Thread starter maka89
  • Start date Start date
  • Tags Tags
    domains
maka89
Messages
66
Reaction score
4
Hello!
I have been studying some pertubation theory lately which i found very useful.
I then started thinking about how to approximate solutions to a 2d boundary value problem if the difficulty lies in the geometry of the boundary(I.e. not rectangular), and not in the diff. equation itself(i.e. the diff. equation has a closed form analytical solution for a rectangular domain).

Does anyone have thoughts on how to approximate such solutions if the domain is close to being rectangular?
 
Last edited:
Physics news on Phys.org
If the boundary geometry is close to the "easy" one, you can perturb it. For example, suppose you have a square whose right side, at ## x=L ##, is a little wonky. You might be able to write your boundary condition as something like ## T(x=L+\epsilon(y),y) = 0 ##. Taylor expand this:

## T(L+\epsilon(y),y) \approx T(L,y) + \frac{\partial T}{\partial x}(L,y)\epsilon(y) = 0 ##. Now put in your perturbative series, ## T = T_0 + \epsilon(y) T_1 ## (I've truncated it at first order to keep life simple!). We get

## T_0(L,y)+\epsilon T_1(L,y)+\frac{\partial T_0}{\partial x}(L,y)\epsilon = 0 ##,

and collecting terms with like powers of ## \epsilon ## gives

## T_0(L,y) = 0 ##,

and

## T_1(L,y) = -\frac{\partial T_0}{\partial x}(L,y) ##.

Notice how this mimicks the thing that usually happens: We get the zeroth order approximation and use it to build the first order one, etc. All the boundary conditions are now in terms of what happens at ## x = L ##. I should note, though, that the ##y## dependence in ##\epsilon## might really complicate the differential equation!
 
Last edited:
Great! thanks for the answer!
But what if the boundary is a little wonky several places and is given for instance as: The value at the curve f(x,y) = 0 should be g(x,y) ? Is there any feasible way of attacking the problem then?

My only hunch is to swith to a curvilinear coordinate system where the boundary is rectangular(I don't know how to do this yet, but am reading up), and treat the terms arising from the scaling factors not being 1 in the differential equation as pertubations.
 
Methods of Theoretical Physics, by Morse and Feshbach, has a whole lot about how to the choose coordinate system to fit the problem domain. You might have a look there! I'm not sure what else could be done for complicated cases, other than resorting to numerical methods.
 
I forgot to mention, if the solution can be thought of as an analytic complex function, then you can sometimes use conformal mapping methods.
 
maka89 said:
Hello!
I have been studying some pertubation theory lately which i found very useful.
I then started thinking about how to approximate solutions to a 2d boundary value problem if the difficulty lies in the geometry of the boundary(I.e. not rectangular), and not in the diff. equation itself(i.e. the diff. equation has a closed form analytical solution for a rectangular domain).

Does anyone have thoughts on how to approximate such solutions if the domain is close to being rectangular?

If you have an analytical parametrisation of each "side" as a function f: [0,1] \to \mathbb{R}^2 then you can construct an analytical map from [0,1]^2 to the domain. If the domain is close to rectangular then the map should be close to affine and the Jacobian should be close to constant.
 
Thread 'Direction Fields and Isoclines'
I sketched the isoclines for $$ m=-1,0,1,2 $$. Since both $$ \frac{dy}{dx} $$ and $$ D_{y} \frac{dy}{dx} $$ are continuous on the square region R defined by $$ -4\leq x \leq 4, -4 \leq y \leq 4 $$ the existence and uniqueness theorem guarantees that if we pick a point in the interior that lies on an isocline there will be a unique differentiable function (solution) passing through that point. I understand that a solution exists but I unsure how to actually sketch it. For example, consider a...
Back
Top