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## Homework Statement

For the curve [tex]y=\sqrt{x}[/tex] , between x = 0and x = 2, find (a) the area under the curve, (b) the arc length, (c) the volume of the solid generated when the area is revolved about the x axis, (d) the curved area of this solid.

## Homework Equations

[tex]ds = \sqrt {1+(y')^{2}}dx[/tex]

## The Attempt at a Solution

I did a and c pretty easily. My problem is arc length. I wrote out the integral [tex]\int^{2}_{0} \sqrt{1+\frac{1}{4x}}dx[/tex] and realized I don't have a clue how to calculate it.Also, for the "curved" area. Does my professor mean surface area? How do I do that?