(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

For the curve [tex]y=\sqrt{x}[/tex] , between x = 0and x = 2, find (a) the area under the curve, (b) the arc length, (c) the volume of the solid generated when the area is revolved about the x axis, (d) the curved area of this solid.

2. Relevant equations

[tex]ds = \sqrt {1+(y')^{2}}dx[/tex]

3. The attempt at a solutionI did a and c pretty easily. My problem is arc length. I wrote out the integral [tex]\int^{2}_{0} \sqrt{1+\frac{1}{4x}}dx[/tex] and realized I don't have a clue how to calculate it.

Also, for the "curved" area. Does my professor mean surface area? How do I do that?

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# Homework Help: Arc length, area

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